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Star Wars: Dawn of the Jedi: Into the Void. Tim Lebbon. Star Wars: Dawn of the Jedi: Into the Void. By. Date de parution : 13/03/14; EAN : 9781473505308; Format : ePub; Nombre de pages: .

Download The Truth About Star Wars in EPUB format Into the Void: Star.Wars.Dawn.of.the.Jedi.Into.the.Void.pdf

Into the Void: Star Wars Legends: Dawn of the Jedi Tim Lebbon. (Dawn of the Jedi - Legends) ISBN: 9780345554493 Language: English.Q:

Why does the combinatorial interpretation of $\sum_n n!p(n)$ give an absurd value in my case?

I'm trying to understand why the following definition of the hypergeometric function appears absurd to me, using some elementary combinatorics.

If we define the hypergeometric function as

_2F_1(a,b,c,z) = \sum_{n=0}^\infty\dfrac{(a)_n(b)_n}{(c)_n}\dfrac{z^n}{n!}

Where $(a)_n = \underbrace{a \times a \times \dots \times a}_n$.

The definition appears rather simple, but it seems we can make a combinatorial interpretation out of it. Let's say we want the left part of the definition, so we can evaluate the LHS

$\sum_{n=0}^\infty\dfrac{(a)_n}{(c)_n}\dfrac{n!}{(n+1)!}z^{n+1}$

We can make the sum into a recursive process, where it should be noted that we can get to $(n+1)$ by subtracting $1$ from $n$, (if $n\geq1$)

So, we have

\begin{align}

\sum_{n=0}^\infty\dfrac{(a)_n}{(c)_n}\dfrac{n!}{(n+1)!}z^{n+1} 0b46394aab

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